If an electrostatically charged object is placed near other objects what will occur
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Ответ:
Ответ:
351 m/s
Explanation:
Given information
Distance between speakers, d= 4 m
Distance between listener and speaker, l= 5 m
Distance moved by the speaker, r= 60 cm = 0.6 m
Frequency, f= 700 Hz
The path difference between two sound waves reaching the listener is half the integral of wavelength for destructive interference to happen hence
Speed of sound,![v=f\lambda= 700 Hz \times 0.502 m= 351 m/s](/tpl/images/0432/2110/f5037.png)