If he leaves the ramp with a speed of 35.0 m/s and has a speed of 33.0 m/s at the top of his trajectory, determine his maximum height (h) (in m) above the end of the ramp. Ignore friction and air resistance.
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Ответ:
H = 6.93 m
Explanation:
given data
velocity v = 35 m/s
horizontal component Vx = 33 m/s
solution
we get here maximum height so first we get vertical component here that is express as
Vy =
.........................1
put here value
Vy =![\sqrt{35^2- 33^2}](/tpl/images/1045/8195/6da6a.png)
Vy = 11.66 m/s
and
now we get height
H =
.............................2
put here value
H =![\frac{11.66^2}{2\times 9.8}](/tpl/images/1045/8195/32180.png)
H = 6.93 m
Ответ:
7/4
Step-by-step explanation: