If in a mechanism the effort moves 6 metres and the load moves 2 metres, what is the velocity ratio?​

The maximum height reached by the ball is 20 m.

Given data:

The height above the ground is, h = 10 m.

The potential energy is, PE = 50 J.

The kinetic energy at ground is, KE = 50 J.

According to conservation of energy, "The total mechanical energy is equal to sum of kinetic energy and potential energy at any point".

ME = KE + PE

ME = 50 J + 50 J

ME = 100 J.

Since, at maximum height, the entire mechanical energy is due to potential energy at that point .

Mechanical energy at maximum height = potential energy at maximum height

ME = PE'

ME = mgH ........................................(1)

Here m is the mass of body,

Substituting the value in equation (1) as,

Thus, the maximum height reached by the ball is 20 m.

Learn more about conservation of energy here:

link