22chandlerlashley
26.07.2019 •
Physics
If the rifle is stopped by the hunter's shoulder in a distance of 3.23 cm, what is the magnitude of the average force exerted on the shoulder by the rifle? answer in units of n
Solved
Show answers
More tips
- A Auto and Moto Battle for the Relocation of The Cherkizovsky Market: Who Won?...
- F Food and Cooking Homemade kvass: recipe and brewing process...
- O Other What is a Disk Emulsifier and How Does it Work?...
- H Health and Medicine How to Calm Your Nerves? Expert Tips That Actually Work...
- A Animals and plants 5 Tips for Taking Care of Yews to Keep Them Green and Beautiful...
- S Sport How to wrap boxing hand wraps? Everything you need to know!...
- F Food and Cooking 10 Reasons Why You Should Avoid Giving Re-Gifts: An Informative Guide...
- F Family and Home Tender Care for Your Parquet: Is it Possible to Clean Parquet?...
- S Style and Beauty How Are Eyelash Extensions Applied? All Your Questions Answered...
- F Food and Cooking 10 Tips for Proper Sushi Consumption...
Ответ:
By conservation of momentum, the initial recoil speed of the rifle is:
u = 904kg * 0.0106 kg / 3.53 kg = 2.7146 m/s
The final recoil speed v is zero in a distance of d = 0.0346 m
So the rifle's acceleration is a = (0 - u^2) / 2*d = -2.7146^2 / 2*.0323 m/s^2
a = -114.07m/s^2
Ответ:
Evidence to puncture the Big Bang Theory