If you apply 3 times the force for 4 times the distance, how much does your work increase?
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Ответ:
Ответ:
Explanation:
= 5 cm = 0.05 m
T = 0.2 s
ω=2π/T=2π/0.2=10πrad/s
When displacement is y, then acceleration, a=−ω2y
Velocity, V=ωr2−y2
Case (a) When y=5cm=0.05m
a=−(10π)2×0.05=−5π2m/s2
V=10π×(0.05)2−(0.05)2=0
Case (b) When y=3cm=0.03m
a=−(10π)2×0.03=−3π2m/s2
V=10π×(0.05)2−(0.03)2=10π×0.04=0.4π m/s
Case (c) When y=0
a=−(10π)2×0=0
V=10π×(0.05)2−02=
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