Physics: If you apply a force of f1 to area a1 on one side of a hydraulic jack, and the second side of the jack has an area that is twice of a1, what will f2 be in comparison to f1

If you apply a force of f1 to area a1 on one side

tdun7003

13.03.2022

$2F_{1}$

Explanation:

F₁ = Force on one side of the jack

A₁ = Area of cross-section of one side of the jack

F₂ = Force on second side of the jack

A₂ = Area of cross-section of second side of the jack = 2 A₁

Using pascal's law

$\frac{F_{1}}{A_{1}}= \frac{F_{_{2}}}{A_{_{2}}}$

$\frac{F_{1}}{A_{1}}= \frac{F_{_{2}}}{2A_{_{1}}}$

$F_{1}= \frac{F_{2}}{2}\\$

$F_{2}= 2F_{1}$

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1963038660

15.12.2021

100 cents = 1$

Explanation:

1 penny is the same as 1 cent so 100 pennys would = 1 dollar hopes this helps.

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