Physics: Imagine that the earth and the-moon have positive charges of the same magnitud. how big isäºthe charge necesary to produce an electrostati, propulsion that equals 1.00% of the-gravitational atraction between twe, bodies

I would say the other way round.Work transfers energy (work is measured in Joules)Power is the rate at which energy is transferred (power is measured in Watts that is Joules/seconds that is a rate of transfer)...

Imagine that the earth and the-moon have positive

Ответ:

Animallover100

01.01.2022

Physics

5.7 x 10^12 C

Explanation:

Let the charge on earth and moon is q.

mass of earth, Me = 5.972 x 10^24 kg

mass of moon, Mm = 7.35 x 10^22 kg

Let d be the distance between earth and moon.

the gravitational force between them is

$F_{g}=G\frac{M_{e} \times M_{m}}{d^{2}}$

The electrostatic force between them is

$F_{e}=\frac{Kq^{2}}{d^{2}}$

According to the question

1 % of Fg = Fe

$0.01 \times 6.67\times10^{-11}\frac{5.97 \times 10^{24}\times7.35 \times 10^{22}}{d^{2}}=9 \times 10^{9}\frac{q^{2}}{d^{2}}$

$2.927 \times 10^{35}=9 \times10^{9}q^{2}$

$3.25 \times 10^{25}=q^{2}$

q = 5.7 x 10^12 C

Thus, the charge on earth and the moon is 5.7 x 10^12 C.

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Imagine that the earth and the-moon have positive charges of the same magnitud. how big isäºthe charge necesary to produce an electrostati, propulsion that equals 1.00% of the-gravitational atraction between twe, bodies

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