twistedhyperboles
06.08.2021 •
Physics
In an x-ray tube, electrons are accelerated through a large voltage and then slammed into a target. This causes the electrons to lose their energy very rapidly. The energy lost from the electron is converted into x-rays. What is the accelerating voltage of an x-ray tube that produces a spectrum of x-rays where the shortest wavelength is 0.039 nm
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Ответ:
The ratio (U₁/U₂) = 6
Explanation:
U, the potential energy is given as
U = kqQ/r
k = Coulomb's constant
q = charge we're concerned about
Q = charge of the negative plate of the capacitor
r = distance of q from the negative plate of the capacitor.
For charge q₁
U₁ = kq₁Q/s
U₂ = kq₂Q/2s
But q₂ = q₁/3
U₂ becomes U₂ = kq₁Q/6s
U₁ = kq₁Q/s
U₂ = kq₁Q/6s
(U₁/U₂) = 6