Physics: In the absence of air resistance, from what height should the diver jump so he hits the water at a speed of 24 m/s? (Set the air resistance slider to none. Adjust the height slider so the diver hits the water with a speed of 24 m/s. )

In the absence of air resistance, from what height

Ответ:

raizagisselle1694

07.02.2022

Physics

Assuming initial is velocity is 0,
Vf^2= v0^2 +2a•x
Vf^2 =2 a•x
Vf^2/2a=x
24^2/2(-9.8)=x
576 / 96.04= 5.875 m

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Ответ:

homelanie21

07.05.2021

Physics

$1.0\times 10^{-6}$ atmospheres are equivalent to $7.6\times 10^{-4}$ millimeters of mercury.

Explanation:

According to current SI unit conversions, 1 atmosphere is equal to 760 millimeters of mercury. The current pressure is determined by simple rule of three:

$p = \frac{760\,mm\,Hg}{1\,atm} \times (1\times 10^{-6}\,atm)$

$p = 7.6\times 10^{-4}\,mm\,Hg$

$1.0\times 10^{-6}$ atmospheres are equivalent to $7.6\times 10^{-4}$ millimeters of mercury.

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In the absence of air resistance, from what height should the diver jump so he hits the water at a speed of 24 m/s? (Set the air resistance
slider to none. Adjust the height slider so the diver hits the water with
a speed of 24 m/s. )

Ответ:

Ответ:

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