SkyeShadow525
14.04.2020 •
Physics
) In the calibration step of a thermochemistry experiment, a current of 117 mA, from a 24.0 V source was allowed to flow through the electrical heater for 247 s and was found to result in an increase in the temperature of the calorimeter and its contents of +1.25 K. Calculate the heat capacity of the calorimeter and its contents
Solved
Show answers
More tips
- F Food and Cooking How to Properly Wash a Down Jacket? Tips from Experts...
- C Computers and Internet Thin Client: What It Is and Why You Need It?...
- F Food and Cooking The Most Delicious and Simple Fish in Batter Recipe...
- F Food and Cooking Red Caviar: How to Choose the Best?...
- C Computers and Internet Clearing Cache: How to Speed Up Your Browser...
- S Style and Beauty How are artificial nails removed?...
- S Style and Beauty Secrets of Tying a Pareo: 5 Ways...
- F Food and Cooking Everything You Need to Know About Pasta...
Answers on questions: Physics
- H History Which body system works with the skeletal system to conduct bodily movement? a) cardiovascular system b) circulatory system c) endocrine system d) muscular system...
- H History Whats this symbol called? ( native american)...
- E English Riddle Am stuck in the same position , but at the same time am always on the move, the only way I reach my destination is when I die. What am I?...
Ответ:
Explanation:
Heat energy supplied = IVt where I = current = 117 A / 1000 = 0.117 A
V = 24 V and t, time = 247 s
Heat energy supplied = 0.117 A × 24V × 247s = 693.576 J
Heat capacity = quantity of heat supplied / rise in temperature
Heat capacity = 693.576 J / 1.25 K = 554.86 J/K
Ответ: