In the diagram, a force of 20 newtons is applied to a block. The block is in dynamic equilibrium. What is the magnitude and direction of the frictional force?
A. 20 newtons in the direction of the applied force
B. 20 newtons opposite to the direction of the applied force
C. 20 newtons perpendicular to the direction of the applied force
D. 20 newtons in two directions, perpendicular and in the direction of the applied force
E. No friction is acting on the block.
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Ответ:
B 20 newtons opposite to the direction of the applied force
Explanation:
Ответ:
Ответ:
number 393 is 1, Number 394 is 2, 395 is 2
Step-by-step explanation:
#393
4/5=x/7, cross multiply28=5xx=5.6#394
h/30=12/h, cross multiplyh^2=360h=square root of 360h=6 square root of 10#395
AC=Xx/4=10/xx^2=40x=2 square root of 10