In the winter activity of tubing, riders slide down snow-covered slopes while sitting on large inflated rubber tubes. To get to the top of the slope, a rider and his tube, with a total mass of 82 kg, are pulled at a constant speed by a tow rope that maintains a constant tension of 310 N. How much thermal energy is created in the slope and the tube during the ascent of a 30-m-high, 120-m-long slope?
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Ответ:
K = 2 10⁻⁸ J
Explanation:
Let's solve this exercise in parts, we start by finding the charge on each plate of the capacitor
C = Q / ΔV
C = ε₀ A / d
ε₀ A / d = Q / ΔV
Q = ε₀ A ΔV / d (1)
indicate the potential difference ΔV₁ = 12 V, the distance between the plates d₁ = 3 mm = 0.003 m,
as the power supply is disconnected and the capacitor is ideal the charge remains constant
in the second part we separate the plates at d₂ = 5 mm = 0.005 m, using equation 1
ΔV₂ =![\frac{Q d_2}{ \epsilon_o A}](/tpl/images/1400/5508/07742.png)
we substitute the equation for Q
ΔV₂ =![\frac{d_2}{\epsilon_o A} \ \frac{\epsilon_o A \Delta V }{d_1}](/tpl/images/1400/5508/f2977.png)
ΔV₂ =![\frac{d_2}{d_1} \ \Delta V_1](/tpl/images/1400/5508/5867c.png)
in the third part we use the concepts of energy
starting point. Test charge near positive plate
Em₀ = U = q ΔV₂
final point. Test charge near negative plate
Em_f = K
energy is conserved
Em₀ = Em_f
q ΔV₂ = K
K = q ΔV₁![\frac{d_2}{d_1}](/tpl/images/1400/5508/a2080.png)
we calculate
K = 1 10⁻⁹ 12 0.005/0.003
K = 2 10⁻⁸ J