robert7248
18.04.2021 •
Physics
Indica que enunciados son falsos y redáctalos de manera que sean verdaderos.
- Thomson descubrió el electrón en un tubo de descarga de gases con el cátodo perforado.
- Millikan observó que la carga del electrón es un múltiplo exacto de una carga elemental.
- En un tubo de descarga de gases, los protones viajan desde el cátodo al ánodo.
Solved
Show answers
More tips
- H Health and Medicine How Did Inna Lose Weight on Dom 2?...
- H Health and Medicine Coughing: Causes, Types, and Treatment Methods...
- H Health and Medicine How to Treat the Flu: A Comprehensive Guide...
- O Other What is a Disk Emulsifier and How Does it Work?...
- F Family and Home What does a newborn need?...
- F Family and Home Choosing the Right Car Seat for Your Child: Tips and Recommendations...
- F Food and Cooking How to Get Reconfirmation of Registration?...
- C Computers and Internet How to Get Rid of Spam in ICQ?...
- A Art and Culture Who Said The Less We Love a Woman, the More She Likes Us ?...
- F Family and Home How to Get Rid of Your Neighbors?...
Answers on questions: Physics
- G Geography Which of the following bodies of water is described in the paragraph above...
- P Physics At a depth of about 10 meters the water pressure on you is equal to the pressure of 1 atmosphere. the total pressure on you is therefore 2 atmospheres1 atm from the...
- B Biology Why are desert soils low in organic matter a. there are not enough plants b. the temperatures are too high c. there are to many grazing animals d. there are not enough...
- S Social Studies According to Polling (2010), what are some issues with the use of PR schedules to evaluate reinforcer potency, generally and with applied populations specifically...
- E English What is the intention of a waiver like the one from funpark? a) to protect the customer b) to enforce penalties c) to solicit sales d) to protect a company...
Ответ:
Explanation:
Weight of car = 13300 N sitting on a piston having cross sectional area of 15 cm
pressure required = force / cross sectional area
= 13300 / π R²
= 13300 / 3.14 x .15²
= 1.88 x 10⁵ N/ m²
force required to lift the car = pressure x area
= 1.88 x 10⁵ x 3.14 x .05² ( 5 cm is radius of small piston )
= 1476 N .