Recall that there is a uniform electric field inside a capacitor. Recall also that in general, LaTeX: V=-\int{\vec{E}\cdot\vec{dl}}V = − ∫ E → ⋅ d l →. In regions of uniform field, this simplifies to LaTeX: V=|\vec{E}|dV = | E → | d, where d is the distance traveled parallel to the electric field. A capacitor with a gap of 0.5 mm has a potential difference from one plate to another of 22 V. What is the magnitude of the electric field within the capacitor? Give your answer in units of kV/m.
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Ответ:
E = 44 kV / m
Explanation:
In a capacitor the potential difference is
ΔV = -E x
E = - ΔV / x
Let's reduce to the SI system
x = 0.5 mm = 0.5 10⁻³ m
Let's calculate
E = 22 / 0.5 10⁻³
E = 44 10³ V / m
E = 44 kV / m
Note that this electric field is uniform
Ответ: