Physics: Sherlock Holmes examines a clue by holding his magnifying glass (with a focal length of 15.0 cm) 10.0 cm away from an object. Find the image distance and the magnification. Describe the image that he observes.

5 electrons because first shell can only have two electrons and second can hold up until 8...

Sherlock Holmes examines a clue by holding his

Ответ:

lovelarissa

20.01.2022

Physics

Distance: -30.0 cm; image is virtual, upright, enlarged

Explanation:

We can find the distance of the image using the lens equation:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}$

where:

f = 15.0 cm is the focal length of the lens (positive for a converging lens)

p = 10.0 cm is the distance of the object from the lens

q is the distance of the image from the lens

Solving for q,

$\frac{1}{q}=\frac{1}{f}-\frac{1}{q}=\frac{1}{15.0}-\frac{1}{10.0}=-0.033\\q=\frac{1}{0.033}=-30.0 cm$

The negative sign tells us that the image is virtual (on the same side of the object, and it cannot be projected on a screen).

The magnification can be found as

$M=-\frac{q}{p}=-\frac{-30}{10}=3$

The magnification gives us the ratio of the size of the image to that of the object: since here |M| = 3, this means that the image is 3 times larger than the object.

Also, the fact that the magnification is positive tells us that the image is upright.

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Sherlock Holmes examines a clue by holding his magnifying glass (with
a focal length of 15.0 cm) 10.0 cm away from an object. Find the image
distance and the magnification. Describe the image that he observes.

Ответ:

Ответ:

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