BabyG1353

25.10.2020 • 

Physics

Suppose a rocket-propelled motorcycle is fi red from rest horizontally across a canyon 1.00 km wide. (a) What minimum constant acceleration in the x-direction must be provided by the engines so the cycle crosses safely if the opposite side is 0.750 km lower than the starting point? (b) At what speed does the motorcycle land if it maintains this constant horizontal component of acceleration? Neglect air drag, but remember that gravity is still acting in the negative y-direction.

Ответ:

dbautis25

06.02.2022

Physics

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Motion equation
x
=
a
t
2
2
x=
2
at
2



y
=
−
g
t
2
2
y=−
2
gt
2



Initial conditions
g
=
9.8
m
s
2
g=9.8
s
2

m


the cycle crosses safely if the...
1000
=
a
t
2
2
1000=
2
at
2



−
750
=
−
g
t
2
2
−750=−
2
gt
2



From this we have acceleration
a
=
1000
⋅
9.8
750
=
13.1
m
s
2
a=
750
1000⋅9.8

=13.1
s
2

m

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Ответ:

Romo2486

14.06.2022

Physics

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I NEEDED THESE POINTS SM THANKS

Explanation:

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