Suppose mercury had 5-to-3 spin-orbit coupling and that its sidereal period remained 88 days, as now. you observe the sun directly overhead in the mercurian sky and then observe again from the same location 88 days later. where will the sun be in the sky? (mercury, like the earth, rotates toward the east.)
a) below the eastern horizon
b) below the western horizon
c) directly overhead again
d) directly on the opposite side of the planet
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Ответ:
d = 513 m
Explanation:
Given that,
An echo returned in 3s.
We need to find the distance of the reflecting surface from the source, given that the speed of sound is 342 m/s.
The sound will cover 2d distance. The formula for the speed is given by :
v = d/t
So,
So, the required distance is 513 m.