suppose you drive 0.6 miles on a road so that the vertical distance changes from 0 to 150 feet. what is the angle of elevation of the road?
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Ответ:
0.32
Explanation:
ke = 1/2mv^2
30 = 1/2 34v^2
30 = 17v^2
v^2 = 30/17
v = sqrt 30/17
v = 0.32