tinasidell1972
26.05.2021 •
Physics
The activity of a sample of caesium-137 is initially 40 kBq. How long will it take for the activity of the sample to fall by 30 kBq? (The half-life of caesium is approximately 30 years.)
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Ответ:
Here, v₂-v₁ = 19 m/s
t₂-t₁ = 2 s
Substitute it into expression,
a = 19/2
a = 9.5 m/s²
So, your final answer is 9.5 m/s²
Hope this helps!