The andromeda galaxy is faintly visible to the naked eye in the constellation andromeda. suppose instead it were located in the same direction in space as the center of the milky way galaxy (but still at its current distance). how would it appear to the eye in that case?

a) we could not see it at all.
b) it would look about the same, but would be in the constellation sagittarius instead of andromeda.
c) it would be much brighter, because it would be illuminated by the many stars in the center of our galaxy.
d) it would look about the same, but it would be harder to pick out because its cloud-like appearance would make it blend in with the cloud-like appearance of the milky way in our sky.

a) We could not see it at all.

Explanation:

The most distant object that can be seen is the andromeda galaxy, which we may have a slight view of. The andromeda galaxy is a large galaxy that along with the previous two is also part of the local group. Spiral-type galaxy that is approximately 250,000 light years in diameter (more than twice the diameter of the Milky Way!) And is about 2.9 million light years away from our galaxy. Because of its distance, we have difficulty visualizing this galaxy, we would have this difficulty even if the andromeda galaxy was in the center of the Milky Way, but maintaining its current distance. That is, even if the andromeda galaxy were located in the same direction in space as the center of the Milky Way (but still at its current distance), we could not see it at all.

Explanation: Two pith ball will repel each other . they will remain balaced due to tension in the spring whose one component balances the weight and the other balances the repulsive force on each.

The gravitational force will be balanced by T cos 27.33 and the electrostatic repulsive force will be balanced by T sin27.33

So

Fg =T cos 27.33

= .55 X .888

= .49 N

Fq = T sin27.33

=.55 x .459

= .25 N.