Physics: The average flow rate in the niagara river is 6.0 × 106 10. kg/s, and the water drops 50 m over niagara falls. if all this energy could be harnessed to generate hydroelec- tric power at 90% efficiency, what would be the electric power output?

The answer is C, an objects ability to not change its motionHope this helps!...

The average flow rate in the niagara river is 6.0 - id60102718, jackievelasquez3424

jamiewest5666

09.03.2022

$2.65\cdot 10^9 W$

Explanation:

The power produced by the water falling down the Falls is

$P=\frac{E}{t}=\frac{mgh}{t}$

where

E = mgh is the potential energy of the water, with m being the mass, g the gravitational acceleration, h the height

t is the time

In this problem we have

$\frac{m}{t}=6.0\cdot 10^6 kg/s$ us the mass flow rate

h = 50 m is the height

g = 9.8 m/s^2 is the acceleration of gravity

Substituting,

$P=(6.0\cdot 10^6 kg/s)(9.8 m/s^2)(50 m)=2.94\cdot 10^9 W$

And since the efficiency is only 90%, the power output is

$P_{out} = (0.90) (2.94\cdot 10^9 W)=2.65\cdot 10^9 W$

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