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longoriafaithe09
16.01.2020 •
Physics
The battery of a flashlight develops 3 v, and the current through the bulb is 200 ma.what power is absorbed by the bulb?
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Ответ:
Answer : The power absorbed by the bulb is, 0.600 W
Explanation :
As we know that,
Power = Voltage × Current
Given:
Voltage = 3 V
Current = 200 mA = 0.200 A
Conversion used : (1 mA = 0.001 A)
Now put all the given values in the above formula, we get:
Power = Voltage × Current
Power = 3V × 0.200 A
Power = 0.600 W
Thus, the power absorbed by the bulb is, 0.600 W
Ответ:
the soup will transfer its thermal energy to the spoon
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