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nakiyapulley7466
25.03.2020 •
Physics
The box moves at a constant speed. If the mass of the box is 4.0 kg, and it is pushed 2.2 m vertically upward, the coefficient of friction is 0.35, and the angle θ is 37°. What is the work done by the force, F? Use g = 10 m/s2.
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Ответ:
24.6 J
Explanation:
First, we have to find the force F. Since the force must overcome the frictional force, it will be equal in magnitude to the frictional force.
To find the frictional force:
Fr = - μ * m * g * cosθ
Fr = - 0.35 * 4 * 10 * cos37
Fr = - 11.18 N
The force F will be 11.18N.
Hence, the work done will be:
W = F * d
W = 11.18 * 2.2
W = 24.6 J
Ответ:
The Answer On Edge Is A.), Have Fun Dreamers!
Step-by-step explanation: