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carriecarl3530
20.03.2020 •
Physics
The center of mass of a 0.30-kg (non-uniform) meter stick is located at its 45-cm mark. What is the magnitude of the torque (in N⋅m) due to gravity if it is supported at the 28-cm mark? (Use g = 9.79 m/s2). (NEVER include units with the answer to ANY numerical question.)
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Ответ:
The magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.
Explanation:
Given that,
Mass of the meter stick, m = 0.3 kg
Center of mass is located at its 45 cm mark.
We need to find the magnitude of the torque due to gravity if it is supported at the 28-cm mark. Torque acting on the object is given by :
or
So, the magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.
Ответ:
C
Explanation:
Both mitochondria and chloroplasts have their own DNA that is different from the nuclear DNA of the larger host cell.
Mitochondrial DNA (mtDNA) and chloroplast DNA (cpDNA) actually more closely resemble the structure of prokaryotic DNA (circular) as compared to the structure of eukaryotic DNA (linear).