The current in a solenoid is 1.2 a. how many turns must be wound on a 0.25 m solenoid in order to produce a magnetic field of 1 mt within it?
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Ответ:
N = 166 turns
Explanation:
Conceptual Analysis
The magnetic field inside a solenoid is calculated by means of the following formula:
B = μ₀*(N/L) *I Formula (1 )
Where:
B : magnetic field inside the sollenoid (T)
μ₀ : free space permeability ( T*m/A)
N : number of turns of the solenoid
L : solenoid length (m)
I : electric current in the solenoid (A)
Known data
I= 1.2 A
L= 0.25 m
B= 1 mT = 1 *10⁻³T
μ₀ = 4π*10⁻⁷ T*m/A
Problem development
We replace data in formula (1) to calculate the number of turns of the solenoid (N):
B = μ₀*(N/L) *I
1 *10⁻³ = 4π*10⁻⁷*(N/0.25) *1.2
1 *10⁻³*0.25 =4π*10⁻⁷*1.2*N
N= (0.25*10⁻³) /(4π*10⁻⁷*1.2)
N= 165.78
N = 166 turns
Ответ:
Explanation:
None of them.
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