The disks you will be using in the lab have the following parameters. All disks are solid with outer radius R1 = 0 0632 m and inner radius R2 = 0 0079 m The masses of the disks are: MT starless steel = 1357kg, MBottom starless stee,ã¼1.344kg. Calculate the moments of inertia of the disks.

MT disc   I = 2,752 10-3 kg m²

MB disc   I = 2,726 10⁻³ kg m²

Explanation:

The moment of inertia given by the expression

        I = ∫ r² dm

for bodies with high symmetry it is tabulated

  for a hollow disk it is

        I = ½ M (R₁² + R₂²)

let's apply this equation to our case

disc MT = 1,357 kg

         I = ½ 1,357 (0.0079² + 0.0632²)

         I = 2,752 10-3 kg m²

disk MB = 1,344 kg

         I = ½ 1,344 (0.0079² + 0.0632²)

         I = 2,726 10⁻³ kg m²

Explanation:

given,

weight of the man = 680 N

weight of the woman = 500 N

mass of man =

  M_m = 69.4 Kg

mass of woman

=

M_w = 51 Kg

ratio of man's kinetic energy Km to that of the woman Kw

momentum is same