The driver or a sports car traveling at 10 m/s steps down hard on the accelerator for 5 seconds. If they accelerate at a rate of 0.25 m/s2, what is the displacement of the car?

53.125m

Explanation:

The displacement of the car, denoted by S, can be calculated using the formula:

S = ut + 1/2at²

Where;

u = initial velocity/speed (m/s)

t = time (s)

a = acceleration (m/s²)

According to the information provided in this question, u = 10m/s, t = 5s, a = 0.25m/s², S = ?

S = ut + 1/2at²

S = (10 × 5) + 1/2 (0.25 × 5²)

S = 50 + 1/2 (0.25 × 25)

S = 50 + 1/2(6.25)

S = 50 + 3.125

S = 53.125m

The required force is

(245 kg) x (9.8 m/s²) x (coefficient of kinetic friction between the pallet and the concrete floor.

Force = 2401 μ  Newtons