rightstrong9827
06.11.2019 •
Physics
The enthalpy of fusion of mercury is 2.292 kj mol-1 at its normal freezing point of 234.3 k; the change in molar volume on melting is +0.517 cm3 mol-1. at what temperature will the bottom of a column of mercury (mass density 13.6 g cm-3) of height 10 m be expected freeze? the pressure at a depth d in a fluid with mass density rho is rhogd, where g is the acceleration of free fall, 9.81 ms-2.
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Ответ:
T_2= 234.37 K
Explanation:
According to Claperyon, we know that
P_1= Atmospheric pressure 760 mm Hg
P_2 = pressure at the bottom of the column
= 10×10^3 mm of Hg+ 760 mm of Hg
= 10760 mm of Hg
now,
P_2-P_1= 10760-760= 10^4 mm
P_2-P_1 ( in pascals) = 10^4× 133.322= 1333220 mm
the enthalpy of fusion (ΔH-fus) of mercury is 2.292 KJ/mol
use the above equation to calculate ΔT as follows
therefore, T_2= 234.37 K
Ответ:
2nd one, 4th one, and then the last one
Step-by-step explanation: