The force P is applied to the 59-kg block when it is at rest. Determine the magnitude and direction of the friction force exerted by the surface on the block if (a) P = 0, (b) P = 198 N, and (c) P = 288 N. (d) What value of P is required to initiate motion up the incline? The static and kinetic coefficients of friction between the block and the incline are μs = 0.20 and μk = 0.16, respectively. The friction force is positive if up the incline, negative if down the incline.
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Ответ:
Explanation:
Coefficient of static friction(μs) = 0.20 Coefficient of kinetic friction (μk) = 0.16
Mass of block (m) = 59kg
acceleration due to gravity (g) = 9.8m/s^2
Normal force = weight of block = mg
Weight of block(W) = 59kg × 9.8m/s^2 = 578.2N
N = 578.2 N
Maximum force of static friction Fs(max) is given by ;
Coefficient of static friction (μs) × N
0.20 × 578.2N = 115.64
As long as P is < 115.64, then the block will remain stationary and thus static frictional force = P (Fs = P)
magnitude and direction of the friction force exerted by the surface on the block if;
(A.) P = 0, Fs = 0
B.) P = 198N;
Fk = μk × N = 0.16 × 578.2 = 92.512N
Fs =
C.) P = 288;
Fk = μk × N = 0.16 × 578.2 =
D.) P value required to initiate motion;
0.2 × 59kg × 9.8m/s^2 = 115.64N
Ответ:
Ed
Explanation:
Dd