The moment of inertia for a 5500 kg solid disc is 12100 kg-m^2. find the radius of the disc? (a) 2.111 m (b) 2.579 m (c) 1.679 m (d) 2.574 m (e) 2.098 m (f) 2.457 m
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Ответ:
The radius of the disc is 2.098 m.
(e) is correct option.
Explanation:
Given that,
Moment of inertia I = 12100 kg-m²
Mass of disc m = 5500 kg
Moment of inertia :
The moment of inertia is equal to the product of the mass and square of the radius.
The moment of inertia of the disc is given by
Where, m = mass of disc
r = radius of the disc
Put the value into the formula
Hence, The radius of the disc is 2.098 m.
Ответ:
1km=1000m
1h=3600s
3600/1000=3.6
Now:
332m/s * 3.6=1195km/h