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britneyvaughn219
14.12.2019 •
Physics
The newly formed xenon nucleus is left in an excited state. thus, when it decays to a state of lower energy a gamma ray is emitted. if the wavelength of the emitted gamma ray is 3.44×10−12 m , what is the decrease in mass, δmxe, of the xenon nucleus as a result of this decay?
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Ответ:
3.87*10^-4
Explanation:
What is the decrease in mass, delta mass Xe , of the xenon nucleus as a result of this deca
We have been given the wavelength of the gamma ray, find the frequency using c = freq*wavelength.
C=f*lambda
3*10^8=f*3.44*10^-12
F=0.87*10^20 hz
Then with the frequency, find the energy emitted using equation
E=hf E = freq*Plank's constant
E=.87*10^20*6.62*10^-34
E=575.94*10^(-16)
With this energy, convert into MeV from joules.
With the energy in MeV, use E=mc^2 using c^2 = 931.5 MeV/u.
Plugging and computing all necessary numbers gives you
3.87*10^-4 u.
Ответ: