Physics: The position of an object that is oscillating on an ideal spring is given by the equation x=(12.3cm)cos[(1.26s−1)t]. (a) at time t=0.815 s, how fast is the object moving?

The position of an object that is oscillating on

Ответ:

hardwick744

15.03.2022

x=((12.3/100)m)cos[(1.26s^−1)t]
v= dx/dt = -((12.3/100)*1.26)sin[(1.26s^−1)t]
v=-((12.3/100)*1.26)sin[(1.26s^−1)t]=-((12.3/100)*1.26)sin[(1.26s^−1)*(0.815)]
v= -0.13261622 m/s
the object moving at 0.13 m/s at time t=0.815 s

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Ответ:

hi510hello

16.01.2022

Physics

The strong base will be dissociated completely into the aqueous solution. The pOH of the solution can be determined by the concentration of the hydroxide ion. The strong bases have lower pOH value.

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The position of an object that is oscillating on an ideal spring is given by the equation x=(12.3cm)cos[(1.26s−1)t]. (a) at time t=0.815 s, how fast is the object moving?

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