Physics: The potential difference between two charged, parallel plates is 200 V and the distance between the plates is 360 cm. Calculate the electric field strength between the plates.

The potential difference between two charged, parallel

bryneosburn

20.01.2022

Explanation:

Given

Potential difference between the plates is $V=200\ V$

Distance between the Plates $d=360\ cm$

Electric Field between the Plates is given by

$E=\frac{V}{d}$

$E=\frac{200}{3.6}$

$E=55.55\ V/m$

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kathyc53

28.04.2023

$35

Step-by-step explanation:

First, multiply the percentage marked down by the price 150x.40=60 to get the price before rebate.

Then, subtract the rebate from the price before rebate 60-25=35 to get the final price.

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