Physics: The slit-to-screen distance is D = 200 cm , and the laser wavelength is 633 nm, use the formula for single-slit diffraction minima to find the slit width a.

The slit-to-screen distance is D = 200 cm , and

Ответ:

lajuannanpf

20.01.2022

Physics

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The slit width $a = \frac{2L \lambda}{W}$

Explanation:

Assuming the unit on the graph is cm

Given that the slit to screen distance is D = 200 cm = 20 000 m

The wavelength $\lambda$ = 633 nm = $633*10^{-9}m$

slit width a = ?

The width of the spot that is the width of the peak from the graph is

W = 1.6 × 2 = 3.2 cm

Where the 1.6 is the distance from 0 to the right end point of the peak

The change in y i.e $\Delta y$ has a formula

$\Delta y$ = Ltanθ

An the width of the spot is 2 × $\Delta y$

W = 2Ltanθ

Applying this formula qsinθ = m $\lambda$

where m = 1 because we a focused on the first zeros ,using small angle approximation we have y

$a\theta = (1) \lambda$

$\theta = \frac{\lambda}{a}$

Substituting this into W = 2ltanθ

Using small angle approximation

W = 2ltanθ = 2Lθ

$W = 2L\frac{\lambda}{a}$

$a = \frac{2L \lambda}{W}$ and this is the slit width

The slit-to-screen distance is D = 200 cm , and the laser wavelength is 633 nm, use the formula for

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Ответ:

alexisozl9253

06.03.2021

Physics

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Explanation:

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The slit-to-screen distance is D = 200 cm , and the laser wavelength is 633 nm, use the formula for single-slit diffraction minima to find the slit width a.

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