Physics: The specifications for an electronic device are 3.00 ± 0.10 amps. if the standard deviation is 0.02, what is the capability index? write your answer to 2 decimal places (x.xx)

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The specifications for an electronic device are 3.00

ewitskarleigh814

13.03.2022

The capability index of the device is 1.67.

Explanation:

It is given that,

The specifications for an electronic device are $(3\pm0.1)\ A$

Upper specification limit, $USL=3+0.1=3.1\ A$

Lower specification limit, $LSL=3-0.1=2.9\ A$

Standard deviation, $\sigma=0.02$

The capability index of an electronic device is given by :

$C_p=\dfrac{USL-LSL}{6\sigma}$

$C_p=\dfrac{3.1-2.9}{6\times 0.02}$

C_p=1.666

C_p=1.67

So, the capability index of the device is 1.67. Hence, this is the required solution.

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