The speed of a box traveling on a horizontal friction surface changes from vi = 13 m/s to vf = 11.5 m/s in a distance of d = 8.5 m. "How long in seconds did it take for the box to slow by this amount, assuming the acceleration is constant?"

"0.68 s" would be taken by the box to slow by this amount.

Given values are:

Initial velocity,

u = 13 m/s

Final velocity,

v = 11.5 m/s

Distance,

d = 8.5 m

As we know,

→            

By substituting the values, we get

→

→    

→                      

                           

hence,

→ Acceleration,

                     

                           

                             

Thus the above response is right.

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0.68 s

Explanation:

We are given that

Initial velocity of box=

Final velocity of box=v=11.5 m/s

Distance=d=8.5 m

We have to find the time taken by box to slow by this amount.

We know that

Substitute the values

We know that

Acceleration=

Substitute the values

Hence, the time taken by box to slow by this amount=0.68 s

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