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coltonwsmith
09.04.2020 •
Physics
The student finds that a standing wave with one antinode is formed on the string when the frequency of the oscillator is f0. The student then moves the oscillator to shorten the horizontal segment of string to a fourth of its original length. At what frequency will a standing wave with one antinode now be formed on the string?
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Ответ:
Explanation:
A standing wave with one antinode in a string means fundamental mode of vibration being formed . In this case
wave length = 2 x length of string
λ = 2L
frequency = velocity of sound / wavelength
= V / 2L
f₀ = V / 2L
new length
l = L / 4
When one antinode now be formed on the string
again fundamental mode of vibration
wave length = 2 x length of string
λ₁ = 2l , λ₁ is new wavelength , l is new length .
frequency = velocity of sound / wavelength
F₀ = V / 2l , F₀ is new frequency,
F₀ = 4V / 2L
= 4 ( V / 2L )
= 4 x f₀
required frequency = 4f₀
four times the previous frequency will be required.
Ответ:
The answer would be FALSE
Explanation:
:)