Physics: To what temperature will 9400J of heat raise 3.5kg of water that is initially at 18.0?C? The specific heat of water is 4186 J/kg?C?.

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To what temperature will 9400J of heat raise 3.5kg

noeminm105

13.02.2022

$T_f=18.641^{\circ} C$

Explanation:

Given that,

Heat raised, Q = 9400 J

Mass, m = 3.5 kg

Initial temperature of water, $T_i=18^{\circ} C$

The specific heat of water, $c=4186\ J/kg^{\circ} C$

We need to find the final temperature of water. The heat required to raise the temperature is given by :

$Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\\dfrac{Q}{mc}=(T_f-T_i)\\\\T_f=\dfrac{Q}{mc}+T_i\\\\T_f=\dfrac{9400}{3.5\times 4186}+18\\\\=18.641^{\circ} C$

So, the final temperature is $18.641^{\circ} C$ .

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