![ninigilford](/avatars/35569.jpg)
ninigilford
19.07.2019 •
Physics
Two astronauts, one of mass 60 kg and the other 90 kg , are initially at rest together in outer space. they then push each other apart. how far apart are they when the lighter astronaut has moved 15 m ?
Solved
Show answers
More tips
- H Health and Medicine How to Treat the Flu: A Comprehensive Guide...
- O Other What is a Disk Emulsifier and How Does it Work?...
- H Health and Medicine How to Calm Your Nerves? Expert Tips That Actually Work...
- A Animals and plants 5 Tips for Taking Care of Yews to Keep Them Green and Beautiful...
- S Sport How to wrap boxing hand wraps? Everything you need to know!...
- F Food and Cooking 10 Reasons Why You Should Avoid Giving Re-Gifts: An Informative Guide...
- F Family and Home Tender Care for Your Parquet: Is it Possible to Clean Parquet?...
- S Style and Beauty How Are Eyelash Extensions Applied? All Your Questions Answered...
- F Food and Cooking 10 Tips for Proper Sushi Consumption...
- S Style and Beauty Learn how to tie a keffiyeh on your head like a pro...
Answers on questions: Physics
- P Physics A constant force of 5.00 N acts on a 2.50 kg object for 10.0 s. What are the changes in the object’s momentum and velocity?...
- M Mathematics Find the solution of the equation from the given numbers y/9 = 32 261 279 288 294...
- M Mathematics What is the approximate value of x round to the nearest 10th...
- C Chemistry 3. A driven gear has 49 teeth and a driver gear has 98 teeth....
- M Mathematics Is this right? i’m unsure if i’m doing this correctly....
- M Mathematics What is the sum of three hundredths plus two?...
Ответ:
F N, as shown in the figure below.
1st astronaut:
The mass is 60 kg.
Let the acceleration be a₁ m/s².
Then
F = 60a₁ (1)
2nd astronaut:
The mass is 90kg.
The acceleration, a₂, is given by
F = 90a₂ (2)
When lighter astronaut has traveled a distance of 15 m, the time taken, t, is given by
(1/2)a₁t² = 15
or
a₁ t² = 30 (3)
The distance traveled by the other astronaut is
d₂ = (1/2)a₂ t² (4)
Substitute (3) into (4)
d₂ = (1/2) a₂ (30/a₁) = 15 (a₂/a₁)
The separation between the astronauts is
D = 15 + d₂ = 15 + 15(a₂/a₁) (5)
From (1) and (2), obtain
60a₁ = 90a₂
a₂/a₁ = 2/3 (6)
Substitute (6) into (5).
D = 15 + 15(2/3) = 25 m
25 m
Ответ: