Physics: Two children sit balanced on a seesaw with the pivot point located at the center of the seesaw. if the first kid has a mass of 36 kg and sits at a distance of 1.2 meters from the pivot, where should the second kid of mass 24 kg sit to balance the see-saw?

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Two children sit balanced on a seesaw with the

Gghbhgy8716

10.01.2022

To solve the problem it is necessary to apply the concepts of Torque and equilibrium.

The Torque is defined as:

$\tau= F*d$

Where

F= Force

d = Distance

In this particular case, the force is caused by the weight of both children.

In turn, when there is equilibrium, the two torques must be equal therefore

$\tau_1 = \tau_2$

m_1gd_1 = m_2_gd_2

m_1d_1 = m_2d_2

Replacing with our values

(36)(1.2)=(24)d_2

Re-arrange to find d_2

$d_2 = \frac{(36)(1.2)}{24}$

d_2 = 1.8m

Therefore the distance that the second kid should sit to balance the see-saw is 1.8m from the pivot.

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