Two circular loops of wire, each containing a single turn, have the same radius of 3.40 cm and a common center. the planes of the loops are perpendicular. each carries a current of 1.80 a. what is the magnitude of the net magnetic field at the common center?
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Ответ:
To solve for the net magnetic field of two circular loops of wire, each containing a single turn
B net= √[( NUI / 2R)^2 × ( NUI / 2R)^2]
Where B net = Net magnetic field
B net = √2 × (NUI/ 2R)
B net =[ √2 × 1 × ( 4 × 3.142 × 10^-7) × (1.8)] ÷ 2 × 0.034
B net = { 1.414 × (0.00000126) × (1.8)}÷ 0.068
B net = 4.72 × 10^-5 T
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