rayastransformers
27.01.2020 •
Physics
Two electrodes connected to a 9.0 v battery are charged to ±45 nc. what is the capacitance of the electrodes?
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Ответ:
= 5 × 10^-9 F
Explanation:
Capacitance is calculated by the formula;
C = Q/V;
where, C is the capacitance, Q is the charge in coulombs and V is the voltage across.
in this case;
Charge = ± 45 × 10^-9 Coulombs
Voltage = 9.0 V
Therefore;
Capacitance = 4.5 × 10^-8 /9
= 5 × 10^-9 F
Ответ: