Physics: two forces act on a 6 kg object. one of the forces is 10 N. if the object accelerates at 2 m/s^2, what is the greatest possible magnitude of the other force

two forces act on a 6 kg object. one of the forces

cw112400

06.02.2022

22N

Explanation:

Let the two forces be acting in the horizontal direction on the object.

Given

Mass m = 6kg

One of the force = 10N

acceleration = 2m/s²

Taking the sum of forces along the x component, we will have:

$\sum F_x = ma_x\\Ff - 10 = 6(2)\\Ff - 10 = 12\\Ff = 12+10\\Ff = 22N$

Note that Ff is the greatest possible magnitude of the other force.

Hence the greatest possible magnitude of the other force is 22N

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jasmin2344

20.12.2020

$p_{x}=$ 0.0135814 kg.m/s

$p_{y}=-0.000219$ kg.m/s

Explanation: When an object with mass is in motion, we say the object has momentum (p). Momentum is dependent on mass and velocity:

p = m.v

The total momentum of Bryce's mice is calculated as

x-axis

$p_{x}=\Sigma m.v_{x}$

$p_{x}=[(0.0213)(0.675)+(0.0165)(-0.249)+(0.0185)(0.395)+(0.0193)(-0.207)]$

$p_{x}=$ 0.0135814

At the x-axis, total momentum of Bryce's mice is 0.0135814 kg.m/s.

y-axis

$p_{y}=\Sigma m.v_{y}$

$p_{y}=[(0.0213)(-0.417)+(0.0165)(-0.809)+(0.0185)(0.953)+(0.0193)(0.227)]$

$p_{y}=-0.000219$

At the y-axis, total momentum of Bryce's mice is -0.000219 kg.m/s.

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