Two identical batteries of emf 12.0 V and internal resistance r = 0.200 are to be connected to an external resistance R, either in parallel or in series. If R =2.00r, what is the current i in the external resistance in the
a. parallel arrangements
b. series arrangements
c. For which arrangement is i greater If R= r/2.00, what is i in the external resistance?
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Ответ:
a. i = 20A
b. i = 40A
c. series arrangement
Explanation:
a. In parallel, total emf E = 12.0v
r = 0.2Ω, R = 2.00r, hence, R = 2.00 x 0.2 = 0.4 Ω,
Recall; E = i (R + r)
12 = i (0.4 + 0.2)
12 = i (0.6)
i = 12/0.6
i = 20 A (for parallel)
b. In series, total emf E = E1 + E2 = 12.0 + 12.0 = 24.0v
r = 0.2Ω, R = 0.4Ω, i = ?
Recall; E = i (R + r)
24 = i (0.4 + 0.2)
i = 24/0.6
i = 40 A
c. If R= r/2.00 in parallel arrangement
R = 0.2/2 = 0.1Ω
E = i (R + r)
12 = i (0.1 + 0.2)
12 = i (0.3)
i = 12/0.3
i = 40A
If R= r/2.00 in series arrangement
R = 0.2/2 = 0.1Ω
E = i (R + r)
24 = i (0.1 + 0.2)
12 = i (0.3)
i = 24/0.3
i = 80A
Hence, i is greater in series arrangement than parallel arrangement
Explanation:
Ответ:
d. Both kinetic and sliding friction
Explanation:
Kinetic friction, commonly known as sliding friction, happens when a body with its surfaces in contact is in relative motion with another. It's the frictional force slowing it down, and finally stopping a moving body. One can describe sliding friction as the resistance any two objects create while sliding against each other. It is often documented as the force required to hold a surface moving along another surface. It is determined by two variables- one is material of the object and another is its weight.