LindaCat78
31.03.2020 •
Physics
Two identical blocks, A and B, are on a horizontal surface, as shown above. There is negligible friction between the surface and the blocks. As shown in Figure 1, block A is initially moving toward block B with speed vA=v0 and block B is initially at rest. Figure 2 shows the blocks in contact as they collide a short time later. In both figures, the location of the center of mass of the two-block system is indicated by the X that is labeled CM.
During the time that the blocks are in contact, describe whether the center of mass of the two-block system is speeding up, slowing down, or staying the same. Speeding up Slowing down Staying the same Briefly describe, in terms of a basic law of physics, whether the center of mass of the two-block system is speeding up,
Solved
Show answers
More tips
- H Health and Medicine Which Water Are You Drinking? Is it Worth Buying Bottled Water?...
- A Animals and plants Уход за джунгариками: полезные советы и рекомендации...
- L Legal consultation What Documents Are Required for a Russian Passport?...
- S Sport How to Choose Tennis Rackets?...
- H Health and Medicine AKDS Vaccination: Ensure Your Child s Safety...
- H Health and Medicine Naskol ko Opasen Ukus Kleshcha i Kak Ego Raspoznat...
- C Computers and Internet How to Delete Your Account on Odnoklassniki...
- H Health and Medicine What to Do When Your Jaw Locks Up?...
- G Goods and services What Are the Most Popular Services?...
Answers on questions: Physics
- P Physics What is the percent of oxygen in In2(SO3)3...
- M Mathematics Use the Distance Formula to find the distance between the two points. G (-2,-6), H (6,9) *...
- B Biology Why is average density important to sea-life...
- M Mathematics Patrick and Mary have a joint account. Their balance at the beginning of June was 7,144.66. During the month they made deposits totaling 1,566.88, wrote checks totaling...
Ответ:
the speed of the center of mass stays the same
Explanation:
In a system with no energy loss, momentum is conserved if the mass remains constant. The system described has no change in mass, and energy loss is considered negligible. Hence the product of the total mass and the velocity of its center will be a constant. The center of mass stays the same speed.
Ответ: