Physics: Two identical loudspeakers that are 5.00 m apart and face toward each other are driven in phase by the same oscillator at a frequency of 875 hz. the speed of sound in the room is 344 m/s. if you start out standing midway between the speakers, find the shortest distance you can walk toward either speaker in order to hear a minimum of sound.

dunno havent read the storyExplanation:...

Two identical loudspeakers that are 5.00 m apart

Serenitybella

06.01.2022

0.0982 m

Explanation:

Given

distance between two loudspeaker is 5 m

frequency (f )=875 Hz

speed of sound (v)=344 m/s

Let x_0 be the smallest distance moved by observer then

Position of observer w.r.t to first speaker is

$x_1=\frac{L}{2}-x_0$

Position of observer w.r.t to second speaker is

$x_2=\frac{L}{2}+x_0$

$\Delta x=2x_0$

For Destructive interference

$\Delta x=\left ( m+\frac{1}{2}\right )\cdot lambda$

For minimum m=0

and $\lambda =\frac{v}{f}$

$2x_0=\frac{v}{2f}$

$x_0=\frac{v}{4f}=\frac{344}{4\times 875}=0.0983 m$

0,0(0 оценок)