potaetoo1997
22.04.2021 •
Physics
Two identical masses are free to slide (without friction) on a horizontal surface. The first mass is attached to two springs. One spring is attached to the wall and has a spring constant of n k, where n is an integer. The second spring is attached to the second mass and has spring constant of k. The two springs have the same relaxed length. The springs are set in motion, such the initial conditions result in the springs oscillating in such a way that the two springs always have equal length at any time. What is n, given the parameters of this problem
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Ответ:
Given that - R = 6 ohm
V = 3 volt
n = ?
so by ohms law , V = I X R
I = V \ R = 3 \ 6 = 0.5 A
we know that I = Q / T here t is 1 sec
Q = I X T = 0.5 X 1 = 0.5 C
By the law of quantization ,
Q = n x e
n = Q / e = 0.5 / 1.6 x 10 ^-19
n = 0.3125 x 10^19
hoped so u got the answer mark me as brainellist :)