Physics: Two infinite nonconducting sheets of charge are parallel to each other, with sheet a in the x = -2.15 plane and sheet b in the x = +2.15 m plane. find the electric field in the region x -2.15 m, in the region x +2.15 m, and between the sheets for the following situations. (a) when each sheet has a uniform surface charge density equal to +3.25 µc/m2 region (m) electric field (n/c) x -2.15 x +2.15 -2.15 x +2.15 (b) when sheet a has a uniform surface charge density equal to +3.25 µc/m2 and sheet b

B. I think Gasoline, natural gas, and diesel fuel I m truly sorry if it s wrong :(Explanation:...

Two infinite nonconducting sheets of charge are

07corcum85504

16.01.2022

a) (-367231.63i , 367231.63i, 0) N/C

b) (0 , 0 , 367231.63i ) N/C

Explanation:

Case x < -2.15

$E =E_{+} + E_{+} \\E = 2*\frac{sigma}{2e_{0} } = \frac{sigma}{e_{0} }\\\\E = \frac{3.25*10^(-6)}{8.85*10^(-12) }\\\\E = - 367231.63 i$

Case x > 2.15

$E =E_{+} + E_{+} \\E = 2*\frac{sigma}{2e_{0} } = \frac{sigma}{e_{0} }\\\\E = \frac{3.25*10^(-6)}{8.85*10^(-12) }\\\\E = +367231.63 i$

Case -2.15 < x <+2.15

$E =E_{+} - E_{+} \\\\E = 0$

Case x < -2.15

$E =E_{+} - E_{+} \\\\E = 0$

Case x > 2.15

$E =E_{+} - E_{+} \\\\E = 0$

Case -2.15 < x <+2.15

$E =E_{+} + E_{-} \\E = 2*\frac{sigma}{2e_{0} } = \frac{sigma}{e_{0} }\\\\E = \frac{3.25*10^(-6)}{8.85*10^(-12) }\\\\E = +367231.63 i$

0,0(0 оценок)