Physics: Two point charges of -7uc and 4uc are a distance of 20 cmapart. how much work does it take to move these charges outto a separation of 90 cm apart @ a constant speed?

If the elevator s speed is constant (in ANY direction) and you can t see out of it, then there s NO measurement you can make inside that will tell you that it s moving. Any weight you measure is normal....

Two point charges of -7uc and 4uc are a distance

Ответ:

wowlol448

02.01.2022

Physics

Approximately 0.979 J.

Explanation:

Assume that the two charges are in vacuum. Apply the coulomb's law to find their initial and final electrical potential energy $\mathrm{EPE}$ .

$\displaystyle \mathrm{EPE} = \frac{k \cdot q_1 \cdot q_2}{r}$ ,

where

The coulomb's constant $k = 8.99\times 10^{9}\; \rm N\cdot m^{2} \cdot C^{-2}$ , q_1

and

are the sizes of the two charges, and

is the separation of (the center of) the two charges.

Note that there's no negative sign before the fraction.

Make sure that all values are in SI units:

$q_1 = -7\rm \;\mu C = -7\times 10^{-6}\; C$ ; $q_2 = 4\rm \;\mu C = 4\times 10^{-6}\; C$ ;Initial separation: $\rm 20\; cm = 0.20\; cm$ ;Final separation: $\rm 90\; cm = 0.90\; cm$ .

Apply Coulomb's law:

Initial potential energy:

$\begin{aligned} \frac{k \cdot q_1 \cdot q_2}{r} &= \frac{8.99\times 10^{9}\times (-7\times 10^{-6})\times 4\times 10^{-6}}{0.20}\\&= \rm -1.2586\; J\end{aligned}$ .

Final potential energy:

$\begin{aligned} \frac{k \cdot q_1 \cdot q_2}{r} &= \frac{8.99\times 10^{9}\times (-7\times 10^{-6})\times 4\times 10^{-6}}{0.90}\\&= \rm -0.279689\; J\end{aligned}$ .

The final potential energy is less negative than the initial one. In other words, the two particles gain energy in this process. The energy difference (final minus initial) will be equal to the work required to move them at a constant speed.

$\begin{aligned}\text{Work required} &= \text{Final EPE} - \text{Initial EPE}\\&= \rm -0.279689\; J - (-1.2586\; J)\\&\approx 0.979\; J\end{aligned}$ .

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Two point charges of -7uc and 4uc are a distance of 20
cmapart. how much work does it take to move these charges outto a
separation of 90 cm apart @ a constant speed?

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