Physics: Two rockets are flying in the same direction and are side by side at the instant their retrorockets fire. rocket a has an initial velocity of +5300 m/s, while rocket b has an initial velocity of +8700 m/s. after a time t both rockets are again side by side, the displacement of each being zero. the acceleration of rocket a is -11 m/s^2. what is the acceleration of rocket b?

step bro was stuck on the elevator Explanation:...

Two rockets are flying in the same direction and

QwesiElorm

02.01.2022

-18.05 m/s^2

Explanation:

Given

Initial velocity of rocket A ( v_A ) 5300m/s

Initial velocity of rocket B( v_B ) 8700 m/s

after time t they have displacement=0

$s_A=5300\times t+\frac{1}{2}\times \left ( -11\right )t^2$

$0=5300\times t+\frac{1}{2}\times \left ( -11\right )t^2$

$t=\frac{5300\times 2}{11}=963.63 s$

for Rocket B

$s_B=8700\times t+\frac{1}{2}\times \left ( a_B\right )t^2$

time is same for A & B

$0=8700\times 963.63+\frac{1}{2}\times \left ( a_B\right )963.63^2$

$a_B=\frac{2\times 8700}{963.63}=-18.05 m/s^2$

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